(3x/3x-1)-(x-7/5x-2)=(-x/(3x-1)(5x-2))

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Solution for (3x/3x-1)-(x-7/5x-2)=(-x/(3x-1)(5x-2)) equation: 



(3x/3x-1)-(x-7/5x-2)=(-x/(3x-1)(5x-2))

We move all terms to the left:

(3x/3x-1)-(x-7/5x-2)-((-x/(3x-1)(5x-2)))=0



Domain of the equation: 3x-1)!=0

x∈R





Domain of the equation: 5x-2)!=0

x∈R





Domain of the equation: (3x-1)(5x-2)))!=0

x∈R



We get rid of parentheses

3x/3x-x+7/5x-((-x/(3x-1)(5x-2)))-1+2=0

We multiply parentheses ..

-((-x/(+15x^2-6x-5x+2)))+3x/3x-x+7/5x-1+2=0

Fractions to decimals

-((-x/(+15x^2-6x-5x+2)))+7/5x-x-1+2+1=0

We calculate fractions

We do not support expression: x^3

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