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(3x/4)+(x/3)-(3x/8)=(1/6)
We move all terms to the left:
(3x/4)+(x/3)-(3x/8)-((1/6))=0
We add all the numbers together, and all the variables
(+3x/4)+(+x/3)-(+3x/8)-((+1/6))=0
We get rid of parentheses
3x/4+x/3-3x/8-((+1/6))=0
We calculate fractions
(-648x^2)/()+3456x^2/()+1536x^2/()+()/()=0
We add all the numbers together, and all the variables
(-648x^2)/()+3456x^2/()+1536x^2/()+1=0
We multiply all the terms by the denominator
(-648x^2)+3456x^2+1536x^2+1*()=0
We add all the numbers together, and all the variables
4992x^2+(-648x^2)=0
We get rid of parentheses
4992x^2-648x^2=0
We add all the numbers together, and all the variables
4344x^2=0
a = 4344; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·4344·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{8688}=0$
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