(3x/4)+(x/3)-(3x/8)=(17x/24)

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Solution for (3x/4)+(x/3)-(3x/8)=(17x/24) equation:



(3x/4)+(x/3)-(3x/8)=(17x/24)
We move all terms to the left:
(3x/4)+(x/3)-(3x/8)-((17x/24))=0
We add all the numbers together, and all the variables
(+3x/4)+(+x/3)-(+3x/8)-((+17x/24))=0
We get rid of parentheses
3x/4+x/3-3x/8-((+17x/24))=0
We calculate fractions
(-2592x^2)/()+13824x^2/()+6144x^2/()+(-((+17x*4*3*8)/()=0
We calculate terms in parentheses: +(-((+17x*4*3*8)/(), so:
-((+17x*4*3*8)/(
We multiply all the terms by the denominator
-((+17x*4*3*8)
We calculate terms in parentheses: -((+17x*4*3*8), so:
(+17x*4*3*8
We calculate terms in parentheses: -((+17x*4*3*8), so:
(+17x*4*3*8
We calculate terms in parentheses: -((+17x*4*3*8), so:
(+17x*4*3*8
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(+17x*4*3*8
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(+17x*4*3*8
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(+17x*4*3*8
We calculate terms in parentheses: -((+17x*4*3*8), so:
(+17x*4*3*8
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(+17x*4*3*8
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(+17x*4*3*8
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(+17x*4*3*8
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(+17x*4*3*8
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(+17x*4*3*8
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(+17x*4*3*8
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(+17x*4*3*8
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(+17x*4*3*8
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(+17x*4*3*8
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