(3x/4)+1=(3/12)

Solution for (3x/4)+1=(3/12) equation:

(3x/4)+1=(3/12)

We move all terms to the left:

(3x/4)+1-((3/12))=0

We add all the numbers together, and all the variables

(+3x/4)+1-((+3/12))=0

We get rid of parentheses

3x/4+1-((+3/12))=0

We calculate fractions


36x^2/()+1+()/()=0

We add all the numbers together, and all the variables

36x^2/()+2=0

We multiply all the terms by the denominator


36x^2+2*()=0

We add all the numbers together, and all the variables

36x^2=0

a = 36; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·36·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{72}=0$