(3x/4)+2x/5)=-46

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Solution for (3x/4)+2x/5)=-46 equation:



(3x/4)+2x/5)=-46
We move all terms to the left:
(3x/4)+2x/5)-(-46)=0
We add all the numbers together, and all the variables
(+3x/4)+2x/5)-(-46)=0
We add all the numbers together, and all the variables
(+3x/4)+2x/5)-(=0
We get rid of parentheses
3x/4+2x/5)-(=0
We calculate fractions
15x^2/()+8x/()=0
We multiply all the terms by the denominator
15x^2+8x=0
a = 15; b = 8; c = 0;
Δ = b2-4ac
Δ = 82-4·15·0
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-8}{2*15}=\frac{-16}{30} =-8/15 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+8}{2*15}=\frac{0}{30} =0 $

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