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(3x/4)-(2x/3)=(2/5)
We move all terms to the left:
(3x/4)-(2x/3)-((2/5))=0
We add all the numbers together, and all the variables
(+3x/4)-(+2x/3)-((+2/5))=0
We get rid of parentheses
3x/4-2x/3-((+2/5))=0
We calculate fractions
(-200x^2)/()+225x^2/()+()/()=0
We add all the numbers together, and all the variables
(-200x^2)/()+225x^2/()+1=0
We multiply all the terms by the denominator
(-200x^2)+225x^2+1*()=0
We add all the numbers together, and all the variables
225x^2+(-200x^2)=0
We get rid of parentheses
225x^2-200x^2=0
We add all the numbers together, and all the variables
25x^2=0
a = 25; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·25·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{50}=0$
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