(3x/7)+(2/7)=2

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Solution for (3x/7)+(2/7)=2 equation: 



(3x/7)+(2/7)=2

We move all terms to the left:

(3x/7)+(2/7)-(2)=0

determiningTheFunctionDomain
(3x/7)-2+(2/7)=0

We add all the numbers together, and all the variables

(+3x/7)-2+(+2/7)=0

We get rid of parentheses

3x/7-2+2/7=0

We multiply all the terms by the denominator


3x+2-2*7=0

We add all the numbers together, and all the variables

3x-12=0

We move all terms containing x to the left, all other terms to the right

3x=12

x=12/3

x=4

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