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(3x^2+2x+10)/(x+3)=0
Domain of the equation: (x+3)!=0We multiply all the terms by the denominator
We move all terms containing x to the left, all other terms to the right
x!=-3
x∈R
(3x^2+2x+10)=0
We get rid of parentheses
3x^2+2x+10=0
a = 3; b = 2; c = +10;
Δ = b2-4ac
Δ = 22-4·3·10
Δ = -116
Delta is less than zero, so there is no solution for the equation
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