(3x2+2x=10)(3x)

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Solution for (3x2+2x=10)(3x) equation:



(3x^2+2x=10)(3x)
We move all terms to the left:
(3x^2+2x-(10)(3x))=0
We get rid of parentheses
3x^2+2x-103x=0
We add all the numbers together, and all the variables
3x^2-101x=0
a = 3; b = -101; c = 0;
Δ = b2-4ac
Δ = -1012-4·3·0
Δ = 10201
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{10201}=101$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-101)-101}{2*3}=\frac{0}{6} =0 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-101)+101}{2*3}=\frac{202}{6} =33+2/3 $

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