(3x2+2x=10)(3x)

Solution for (3x2+2x=10)(3x) equation:

(3x^2+2x=10)(3x)

We move all terms to the left:

(3x^2+2x-(10)(3x))=0

We get rid of parentheses

3x^2+2x-103x=0

We add all the numbers together, and all the variables

3x^2-101x=0

a = 3; b = -101; c = 0;
Δ = b2-4ac
Δ = -1012-4·3·0
Δ = 10201
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{10201}=101$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-101)-101}{2*3}=\frac{0}{6}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-101)+101}{2*3}=\frac{202}{6}
=33+2/3
$