(3x2-2x+5)+(-2x2+3x-2)=x2-x+3

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Solution for (3x2-2x+5)+(-2x2+3x-2)=x2-x+3 equation: 



(3x^2-2x+5)+(-2x^2+3x-2)=x2-x+3

We move all terms to the left:

(3x^2-2x+5)+(-2x^2+3x-2)-(x2-x+3)=0

We add all the numbers together, and all the variables

(-2x^2+3x-2)-(+x^2-1x+3)+(3x^2-2x+5)=0

We get rid of parentheses

-2x^2-x^2+3x^2+3x+1x-2x-2-3+5=0

We add all the numbers together, and all the variables

2x=0

x=0/2

x=0

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