(3x=18)+(9x-27)=99

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Solution for (3x=18)+(9x-27)=99 equation: 



(3x=18)+(9x-27)=99

We move all terms to the left:

(3x-(18)+(9x-27))=0



We calculate terms in parentheses: +(3x-18+(9x-27)), so:

3x-18+(9x-27)

determiningTheFunctionDomain
3x+(9x-27)-18

We get rid of parentheses

3x+9x-27-18

We add all the numbers together, and all the variables

12x-45

Back to the equation:

+(12x-45)



We get rid of parentheses

12x-45=0

We move all terms containing x to the left, all other terms to the right

12x=45

x=45/12

x=3+3/4

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