(3x=4)+(7x-8)

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Solution for (3x=4)+(7x-8) equation: 



(3x=4)+(7x-8)

We move all terms to the left:

(3x-(4)+(7x-8))=0



We calculate terms in parentheses: +(3x-4+(7x-8)), so:

3x-4+(7x-8)

determiningTheFunctionDomain
3x+(7x-8)-4

We get rid of parentheses

3x+7x-8-4

We add all the numbers together, and all the variables

10x-12

Back to the equation:

+(10x-12)



We get rid of parentheses

10x-12=0

We move all terms containing x to the left, all other terms to the right

10x=12

x=12/10

x=1+1/5

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