(3xa)+(4xb)+c=33

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Solution for (3xa)+(4xb)+c=33 equation:


Simplifying
(3xa) + (4xb) + c = 33

Solving
(3ax) + (4bx) + c = 33

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '(-4bx)' to each side of the equation.
(3ax) + (4bx) + (-4bx) + c = 33 + (-4bx)

Combine like terms: (4bx) + (-4bx) = 0
(3ax) + 0 + c = 33 + (-4bx)
(3ax) + c = 33 + (-4bx)

Add '-1c' to each side of the equation.
(3ax) + c + -1c = 33 + (-4bx) + -1c

Combine like terms: c + -1c = 0
(3ax) + 0 = 33 + (-4bx) + -1c
(3ax) = 33 + (-4bx) + -1c

Divide each side by '(3x)'.
a = 11x-1 + (-1.333333333b) + -0.3333333333cx-1

Simplifying
a = 11x-1 + (-1.333333333b) + -0.3333333333cx-1

Reorder the terms:
a = (-1.333333333b) + -0.3333333333cx-1 + 11x-1

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