(3y+1)+(2y+2)=132

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Solution for (3y+1)+(2y+2)=132 equation:


Simplifying
(3y + 1) + (2y + 2) = 132

Reorder the terms:
(1 + 3y) + (2y + 2) = 132

Remove parenthesis around (1 + 3y)
1 + 3y + (2y + 2) = 132

Reorder the terms:
1 + 3y + (2 + 2y) = 132

Remove parenthesis around (2 + 2y)
1 + 3y + 2 + 2y = 132

Reorder the terms:
1 + 2 + 3y + 2y = 132

Combine like terms: 1 + 2 = 3
3 + 3y + 2y = 132

Combine like terms: 3y + 2y = 5y
3 + 5y = 132

Solving
3 + 5y = 132

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + 5y = 132 + -3

Combine like terms: 3 + -3 = 0
0 + 5y = 132 + -3
5y = 132 + -3

Combine like terms: 132 + -3 = 129
5y = 129

Divide each side by '5'.
y = 25.8

Simplifying
y = 25.8

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