(3y+1)+(2y+2)=48

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Solution for (3y+1)+(2y+2)=48 equation: 



(3y+1)+(2y+2)=48

We move all terms to the left:

(3y+1)+(2y+2)-(48)=0

We get rid of parentheses

3y+2y+1+2-48=0

We add all the numbers together, and all the variables

5y-45=0

We move all terms containing y to the left, all other terms to the right

5y=45

y=45/5

y=9

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