(3y+1)/4=2-(3-2y)/6

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Solution for (3y+1)/4=2-(3-2y)/6 equation: 



(3y+1)/4=2-(3-2y)/6

We move all terms to the left:

(3y+1)/4-(2-(3-2y)/6)=0

We add all the numbers together, and all the variables

(3y+1)/4-(2-(-2y+3)/6)=0

We calculate fractions


3y/()+(-(2-(-2y+3)*4)/()=0



We calculate terms in parentheses: +(-(2-(-2y+3)*4)/(), so:

-(2-(-2y+3)*4)/(

We multiply all the terms by the denominator


-(2-(-2y+3)*4)



We calculate terms in parentheses: -(2-(-2y+3)*4), so:

2-(-2y+3)*4

determiningTheFunctionDomain
-(-2y+3)*4+2

We multiply parentheses

8y-12+2

We add all the numbers together, and all the variables

8y-10

Back to the equation:

-(8y-10)



We get rid of parentheses

-8y+10

Back to the equation:

+(-8y+10)



We get rid of parentheses

3y/()-8y+10=0

We multiply all the terms by the denominator


3y-8y*()+10*()=0

We add all the numbers together, and all the variables

3y-8y*()=0

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