(3y+1)=(4y-12)

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Solution for (3y+1)=(4y-12) equation:


Simplifying
(3y + 1) = (4y + -12)

Reorder the terms:
(1 + 3y) = (4y + -12)

Remove parenthesis around (1 + 3y)
1 + 3y = (4y + -12)

Reorder the terms:
1 + 3y = (-12 + 4y)

Remove parenthesis around (-12 + 4y)
1 + 3y = -12 + 4y

Solving
1 + 3y = -12 + 4y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-4y' to each side of the equation.
1 + 3y + -4y = -12 + 4y + -4y

Combine like terms: 3y + -4y = -1y
1 + -1y = -12 + 4y + -4y

Combine like terms: 4y + -4y = 0
1 + -1y = -12 + 0
1 + -1y = -12

Add '-1' to each side of the equation.
1 + -1 + -1y = -12 + -1

Combine like terms: 1 + -1 = 0
0 + -1y = -12 + -1
-1y = -12 + -1

Combine like terms: -12 + -1 = -13
-1y = -13

Divide each side by '-1'.
y = 13

Simplifying
y = 13

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