(3y+1)=28

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Solution for (3y+1)=28 equation: 



(3y+1)=28

We move all terms to the left:

(3y+1)-(28)=0

We get rid of parentheses

3y+1-28=0

We add all the numbers together, and all the variables

3y-27=0

We move all terms containing y to the left, all other terms to the right

3y=27

y=27/3

y=9

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