(3y+11)+(4y+1)=180

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Solution for (3y+11)+(4y+1)=180 equation: 



(3y+11)+(4y+1)=180

We move all terms to the left:

(3y+11)+(4y+1)-(180)=0

We get rid of parentheses

3y+4y+11+1-180=0

We add all the numbers together, and all the variables

7y-168=0

We move all terms containing y to the left, all other terms to the right

7y=168

y=168/7

y=24

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