(3y+12)+(y+12)+41=0

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Solution for (3y+12)+(y+12)+41=0 equation:


Simplifying
(3y + 12) + (y + 12) + 41 = 0

Reorder the terms:
(12 + 3y) + (y + 12) + 41 = 0

Remove parenthesis around (12 + 3y)
12 + 3y + (y + 12) + 41 = 0

Reorder the terms:
12 + 3y + (12 + y) + 41 = 0

Remove parenthesis around (12 + y)
12 + 3y + 12 + y + 41 = 0

Reorder the terms:
12 + 12 + 41 + 3y + y = 0

Combine like terms: 12 + 12 = 24
24 + 41 + 3y + y = 0

Combine like terms: 24 + 41 = 65
65 + 3y + y = 0

Combine like terms: 3y + y = 4y
65 + 4y = 0

Solving
65 + 4y = 0

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-65' to each side of the equation.
65 + -65 + 4y = 0 + -65

Combine like terms: 65 + -65 = 0
0 + 4y = 0 + -65
4y = 0 + -65

Combine like terms: 0 + -65 = -65
4y = -65

Divide each side by '4'.
y = -16.25

Simplifying
y = -16.25

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