(3y+177-23y)+(20y+3)=180

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Solution for (3y+177-23y)+(20y+3)=180 equation: 



(3y+177-23y)+(20y+3)=180

We move all terms to the left:

(3y+177-23y)+(20y+3)-(180)=0

We add all the numbers together, and all the variables

(-20y+177)+(20y+3)-180=0

We get rid of parentheses

-20y+20y+177+3-180=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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