(3y+2)(y+9)=0

Solution for (3y+2)(y+9)=0 equation:

(3y+2)(y+9)=0

We multiply parentheses ..

(+3y^2+27y+2y+18)=0

We get rid of parentheses

3y^2+27y+2y+18=0

We add all the numbers together, and all the variables

3y^2+29y+18=0

a = 3; b = 29; c = +18;
Δ = b2-4ac
Δ = 292-4·3·18
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{625}=25$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(29)-25}{2*3}=\frac{-54}{6}
=-9
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(29)+25}{2*3}=\frac{-4}{6}
=-2/3
$