(3y+2)+3y=127

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Solution for (3y+2)+3y=127 equation: 



(3y+2)+3y=127

We move all terms to the left:

(3y+2)+3y-(127)=0

We add all the numbers together, and all the variables

3y+(3y+2)-127=0

We get rid of parentheses

3y+3y+2-127=0

We add all the numbers together, and all the variables

6y-125=0

We move all terms containing y to the left, all other terms to the right

6y=125

y=125/6

y=20+5/6

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