(3y+2)=(11y-32)

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Solution for (3y+2)=(11y-32) equation: 



(3y+2)=(11y-32)

We move all terms to the left:

(3y+2)-((11y-32))=0

We get rid of parentheses

3y-((11y-32))+2=0



We calculate terms in parentheses: -((11y-32)), so:

(11y-32)

We get rid of parentheses

11y-32

Back to the equation:

-(11y-32)



We get rid of parentheses

3y-11y+32+2=0

We add all the numbers together, and all the variables

-8y+34=0

We move all terms containing y to the left, all other terms to the right

-8y=-34

y=-34/-8

y=4+1/4

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