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(3y+2)=(4y+3)
We move all terms to the left:
(3y+2)-((4y+3))=0
We get rid of parentheses
3y-((4y+3))+2=0
We calculate terms in parentheses: -((4y+3)), so:We get rid of parentheses
(4y+3)
We get rid of parentheses
4y+3
Back to the equation:
-(4y+3)
3y-4y-3+2=0
We add all the numbers together, and all the variables
-1y-1=0
We move all terms containing y to the left, all other terms to the right
-y=1
y=1/-1
y=-1
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