(3y+20)=(5y-26)

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Solution for (3y+20)=(5y-26) equation: 



(3y+20)=(5y-26)

We move all terms to the left:

(3y+20)-((5y-26))=0

We get rid of parentheses

3y-((5y-26))+20=0



We calculate terms in parentheses: -((5y-26)), so:

(5y-26)

We get rid of parentheses

5y-26

Back to the equation:

-(5y-26)



We get rid of parentheses

3y-5y+26+20=0

We add all the numbers together, and all the variables

-2y+46=0

We move all terms containing y to the left, all other terms to the right

-2y=-46

y=-46/-2

y=+23

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