(3y+20)=(5y-26)

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Solution for (3y+20)=(5y-26) equation:



(3y+20)=(5y-26)
We move all terms to the left:
(3y+20)-((5y-26))=0
We get rid of parentheses
3y-((5y-26))+20=0
We calculate terms in parentheses: -((5y-26)), so:
(5y-26)
We get rid of parentheses
5y-26
Back to the equation:
-(5y-26)
We get rid of parentheses
3y-5y+26+20=0
We add all the numbers together, and all the variables
-2y+46=0
We move all terms containing y to the left, all other terms to the right
-2y=-46
y=-46/-2
y=+23

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