(3y+29)+(3y-17)=180

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Solution for (3y+29)+(3y-17)=180 equation: 



(3y+29)+(3y-17)=180

We move all terms to the left:

(3y+29)+(3y-17)-(180)=0

We get rid of parentheses

3y+3y+29-17-180=0

We add all the numbers together, and all the variables

6y-168=0

We move all terms containing y to the left, all other terms to the right

6y=168

y=168/6

y=28

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