(3y+3)+(3y+3)+(4y-1)+(4y-1)=158

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Solution for (3y+3)+(3y+3)+(4y-1)+(4y-1)=158 equation: 



(3y+3)+(3y+3)+(4y-1)+(4y-1)=158

We move all terms to the left:

(3y+3)+(3y+3)+(4y-1)+(4y-1)-(158)=0

We get rid of parentheses

3y+3y+4y+4y+3+3-1-1-158=0

We add all the numbers together, and all the variables

14y-154=0

We move all terms containing y to the left, all other terms to the right

14y=154

y=154/14

y=11

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