(3y+3)+(5c+2)=

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Solution for (3y+3)+(5c+2)= equation:


Simplifying
(3y + 3) + (5c + 2) = 0

Reorder the terms:
(3 + 3y) + (5c + 2) = 0

Remove parenthesis around (3 + 3y)
3 + 3y + (5c + 2) = 0

Reorder the terms:
3 + 3y + (2 + 5c) = 0

Remove parenthesis around (2 + 5c)
3 + 3y + 2 + 5c = 0

Reorder the terms:
3 + 2 + 5c + 3y = 0

Combine like terms: 3 + 2 = 5
5 + 5c + 3y = 0

Solving
5 + 5c + 3y = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-5' to each side of the equation.
5 + 5c + -5 + 3y = 0 + -5

Reorder the terms:
5 + -5 + 5c + 3y = 0 + -5

Combine like terms: 5 + -5 = 0
0 + 5c + 3y = 0 + -5
5c + 3y = 0 + -5

Combine like terms: 0 + -5 = -5
5c + 3y = -5

Add '-3y' to each side of the equation.
5c + 3y + -3y = -5 + -3y

Combine like terms: 3y + -3y = 0
5c + 0 = -5 + -3y
5c = -5 + -3y

Divide each side by '5'.
c = -1 + -0.6y

Simplifying
c = -1 + -0.6y

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