(3y+3)+4y=118

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Solution for (3y+3)+4y=118 equation: 



(3y+3)+4y=118

We move all terms to the left:

(3y+3)+4y-(118)=0

We add all the numbers together, and all the variables

4y+(3y+3)-118=0

We get rid of parentheses

4y+3y+3-118=0

We add all the numbers together, and all the variables

7y-115=0

We move all terms containing y to the left, all other terms to the right

7y=115

y=115/7

y=16+3/7

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