(3y+32)+(3y-2)=4

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Solution for (3y+32)+(3y-2)=4 equation: 



(3y+32)+(3y-2)=4

We move all terms to the left:

(3y+32)+(3y-2)-(4)=0

We get rid of parentheses

3y+3y+32-2-4=0

We add all the numbers together, and all the variables

6y+26=0

We move all terms containing y to the left, all other terms to the right

6y=-26

y=-26/6

y=-4+1/3

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