(3y+4)+(2Y+16)=180

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Solution for (3y+4)+(2Y+16)=180 equation:



(3y+4)+(2+16)=180
We move all terms to the left:
(3y+4)+(2+16)-(180)=0
determiningTheFunctionDomain (3y+4)-180+(2+16)=0
We add all the numbers together, and all the variables
(3y+4)-180+18=0
We add all the numbers together, and all the variables
(3y+4)-162=0
We get rid of parentheses
3y+4-162=0
We add all the numbers together, and all the variables
3y-158=0
We move all terms containing y to the left, all other terms to the right
3y=158
y=158/3
y=52+2/3

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