(3y+4)-7=8+2y

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Solution for (3y+4)-7=8+2y equation: 



(3y+4)-7=8+2y

We move all terms to the left:

(3y+4)-7-(8+2y)=0

We add all the numbers together, and all the variables

(3y+4)-(2y+8)-7=0

We get rid of parentheses

3y-2y+4-8-7=0

We add all the numbers together, and all the variables

y-11=0

We move all terms containing y to the left, all other terms to the right

y=11

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