(3y+4)/(2-5y)=-1/2

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Solution for (3y+4)/(2-5y)=-1/2 equation: 



(3y+4)/(2-5y)=-1/2

We move all terms to the left:

(3y+4)/(2-5y)-(-1/2)=0



Domain of the equation: (2-5y)!=0

We move all terms containing y to the left, all other terms to the right

-5y!=-2

y!=-2/-5

y!=2/5

y∈R



We add all the numbers together, and all the variables

(3y+4)/(-5y+2)-(-1/2)=0

We get rid of parentheses

(3y+4)/(-5y+2)+1/2=0

We calculate fractions


(6y+8)/(-10y+4)+(1*(-5y+2))/(-10y+4)=0



We calculate terms in parentheses: +(1*(-5y+2))/(-10y+4), so:

1*(-5y+2))/(-10y+4

We add all the numbers together, and all the variables

-10y+1*(-5y+2))/(+4

We multiply all the terms by the denominator


-10y*(+1*(-5y+2))+4*(

We add all the numbers together, and all the variables

-10y*(+1*(-5y+2))

Back to the equation:

+(-10y*(+1*(-5y+2)))



We multiply all the terms by the denominator


(6y+8)+((-10y*(+1*(-5y+2))))*(-10y+4)=0



We calculate terms in parentheses: +((-10y*(+1*(-5y+2))))*(-10y+4), so:

(-10y*(+1*(-5y+2))))*(-10y+4

We add all the numbers together, and all the variables

-10y+(-10y*(+1*(-5y+2))))*(+4

Back to the equation:

+(-10y+(-10y*(+1*(-5y+2))))*(+4)



We add all the numbers together, and all the variables

(6y+8)+(-10y+(-10y*(+1*(-5y+2))))*4=0

We get rid of parentheses

6y+(-10y+(-10y*(+1*(-5y+2))))*4+8=0

We move all terms containing y to the left, all other terms to the right

6y+(-10y+(-10y*(+1*(-5y+2))))*4=-8

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