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(3y+4)=(5-2y)
We move all terms to the left:
(3y+4)-((5-2y))=0
We add all the numbers together, and all the variables
(3y+4)-((-2y+5))=0
We get rid of parentheses
3y-((-2y+5))+4=0
We calculate terms in parentheses: -((-2y+5)), so:We get rid of parentheses
(-2y+5)
We get rid of parentheses
-2y+5
Back to the equation:
-(-2y+5)
3y+2y-5+4=0
We add all the numbers together, and all the variables
5y-1=0
We move all terms containing y to the left, all other terms to the right
5y=1
y=1/5
y=1/5
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