(3y+5)+(2y+4)=10y-31

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Solution for (3y+5)+(2y+4)=10y-31 equation: 



(3y+5)+(2y+4)=10y-31

We move all terms to the left:

(3y+5)+(2y+4)-(10y-31)=0

We get rid of parentheses

3y+2y-10y+5+4+31=0

We add all the numbers together, and all the variables

-5y+40=0

We move all terms containing y to the left, all other terms to the right

-5y=-40

y=-40/-5

y=+8

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