(3y+5)/(2y+4)=2

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Solution for (3y+5)/(2y+4)=2 equation: 



(3y+5)/(2y+4)=2

We move all terms to the left:

(3y+5)/(2y+4)-(2)=0



Domain of the equation: (2y+4)!=0

We move all terms containing y to the left, all other terms to the right

2y!=-4

y!=-4/2

y!=-2

y∈R



We multiply all the terms by the denominator


(3y+5)-2*(2y+4)=0

We multiply parentheses

(3y+5)-4y-8=0

We get rid of parentheses

3y-4y+5-8=0

We add all the numbers together, and all the variables

-1y-3=0

We move all terms containing y to the left, all other terms to the right

-y=3

y=3/-1

y=-3

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