(3y+52)=(7y-55)

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Solution for (3y+52)=(7y-55) equation: 



(3y+52)=(7y-55)

We move all terms to the left:

(3y+52)-((7y-55))=0

We get rid of parentheses

3y-((7y-55))+52=0



We calculate terms in parentheses: -((7y-55)), so:

(7y-55)

We get rid of parentheses

7y-55

Back to the equation:

-(7y-55)



We get rid of parentheses

3y-7y+55+52=0

We add all the numbers together, and all the variables

-4y+107=0

We move all terms containing y to the left, all other terms to the right

-4y=-107

y=-107/-4

y=26+3/4

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