(3y+6)/3=2y+2

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Solution for (3y+6)/3=2y+2 equation: 



(3y+6)/3=2y+2

We move all terms to the left:

(3y+6)/3-(2y+2)=0

We get rid of parentheses

(3y+6)/3-2y-2=0

We multiply all the terms by the denominator


(3y+6)-2y*3-2*3=0

We add all the numbers together, and all the variables

(3y+6)-2y*3-6=0

Wy multiply elements

(3y+6)-6y-6=0

We get rid of parentheses

3y-6y+6-6=0

We add all the numbers together, and all the variables

-3y=0

y=0/-3

y=0

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