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(3y+6)=(2y+10)
We move all terms to the left:
(3y+6)-((2y+10))=0
We get rid of parentheses
3y-((2y+10))+6=0
We calculate terms in parentheses: -((2y+10)), so:We get rid of parentheses
(2y+10)
We get rid of parentheses
2y+10
Back to the equation:
-(2y+10)
3y-2y-10+6=0
We add all the numbers together, and all the variables
y-4=0
We move all terms containing y to the left, all other terms to the right
y=4
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