(3y+72)=(-7y+22)

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Solution for (3y+72)=(-7y+22) equation: 



(3y+72)=(-7y+22)

We move all terms to the left:

(3y+72)-((-7y+22))=0

We get rid of parentheses

3y-((-7y+22))+72=0



We calculate terms in parentheses: -((-7y+22)), so:

(-7y+22)

We get rid of parentheses

-7y+22

Back to the equation:

-(-7y+22)



We get rid of parentheses

3y+7y-22+72=0

We add all the numbers together, and all the variables

10y+50=0

We move all terms containing y to the left, all other terms to the right

10y=-50

y=-50/10

y=-5

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