(3y+z)+(z-5y)-(2z-2y)=

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Solution for (3y+z)+(z-5y)-(2z-2y)= equation: 


Simplifying
(3y + z) + (z + -5y) + -1(2z + -2y) = 0

Remove parenthesis around (3y + z)
3y + z + (z + -5y) + -1(2z + -2y) = 0

Reorder the terms:
3y + z + (-5y + z) + -1(2z + -2y) = 0

Remove parenthesis around (-5y + z)
3y + z + -5y + z + -1(2z + -2y) = 0

Reorder the terms:
3y + z + -5y + z + -1(-2y + 2z) = 0
3y + z + -5y + z + (-2y * -1 + 2z * -1) = 0
3y + z + -5y + z + (2y + -2z) = 0

Reorder the terms:
3y + -5y + 2y + z + z + -2z = 0

Combine like terms: 3y + -5y = -2y
-2y + 2y + z + z + -2z = 0

Combine like terms: -2y + 2y = 0
0 + z + z + -2z = 0
z + z + -2z = 0

Combine like terms: z + z = 2z
2z + -2z = 0

Combine like terms: 2z + -2z = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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