(3y-1)-(2y+4)+y=33

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Solution for (3y-1)-(2y+4)+y=33 equation: 



(3y-1)-(2y+4)+y=33

We move all terms to the left:

(3y-1)-(2y+4)+y-(33)=0

We add all the numbers together, and all the variables

y+(3y-1)-(2y+4)-33=0

We get rid of parentheses

y+3y-2y-1-4-33=0

We add all the numbers together, and all the variables

2y-38=0

We move all terms containing y to the left, all other terms to the right

2y=38

y=38/2

y=19

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