(3y-1)=(2y+7)

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Solution for (3y-1)=(2y+7) equation: 



(3y-1)=(2y+7)

We move all terms to the left:

(3y-1)-((2y+7))=0

We get rid of parentheses

3y-((2y+7))-1=0



We calculate terms in parentheses: -((2y+7)), so:

(2y+7)

We get rid of parentheses

2y+7

Back to the equation:

-(2y+7)



We get rid of parentheses

3y-2y-7-1=0

We add all the numbers together, and all the variables

y-8=0

We move all terms containing y to the left, all other terms to the right

y=8

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