(3y-15)=(2y+10)

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Solution for (3y-15)=(2y+10) equation: 



(3y-15)=(2y+10)

We move all terms to the left:

(3y-15)-((2y+10))=0

We get rid of parentheses

3y-((2y+10))-15=0



We calculate terms in parentheses: -((2y+10)), so:

(2y+10)

We get rid of parentheses

2y+10

Back to the equation:

-(2y+10)



We get rid of parentheses

3y-2y-10-15=0

We add all the numbers together, and all the variables

y-25=0

We move all terms containing y to the left, all other terms to the right

y=25

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