(3y-15)=(8y+32)+3

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Solution for (3y-15)=(8y+32)+3 equation: 



(3y-15)=(8y+32)+3

We move all terms to the left:

(3y-15)-((8y+32)+3)=0

We get rid of parentheses

3y-((8y+32)+3)-15=0



We calculate terms in parentheses: -((8y+32)+3), so:

(8y+32)+3

We get rid of parentheses

8y+32+3

We add all the numbers together, and all the variables

8y+35

Back to the equation:

-(8y+35)



We get rid of parentheses

3y-8y-35-15=0

We add all the numbers together, and all the variables

-5y-50=0

We move all terms containing y to the left, all other terms to the right

-5y=50

y=50/-5

y=-10

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