(3y-17)=6(7)+20

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Solution for (3y-17)=6(7)+20 equation: 



(3y-17)=6(7)+20

We move all terms to the left:

(3y-17)-(6(7)+20)=0

We add all the numbers together, and all the variables

(3y-17)-87=0

We get rid of parentheses

3y-17-87=0

We add all the numbers together, and all the variables

3y-104=0

We move all terms containing y to the left, all other terms to the right

3y=104

y=104/3

y=34+2/3

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