(3y-2)+(3y-2)+(y/6)+(y/6)=34

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Solution for (3y-2)+(3y-2)+(y/6)+(y/6)=34 equation: 



(3y-2)+(3y-2)+(y/6)+(y/6)=34

We move all terms to the left:

(3y-2)+(3y-2)+(y/6)+(y/6)-(34)=0

We add all the numbers together, and all the variables

(3y-2)+(3y-2)+(+y/6)+(+y/6)-34=0

We get rid of parentheses

3y+3y+y/6+y/6-2-2-34=0

We multiply all the terms by the denominator


3y*6+3y*6+y+y-2*6-2*6-34*6=0

We add all the numbers together, and all the variables

2y+3y*6+3y*6-228=0

Wy multiply elements

2y+18y+18y-228=0

We add all the numbers together, and all the variables

38y-228=0

We move all terms containing y to the left, all other terms to the right

38y=228

y=228/38

y=6

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