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(3y-2)/(2y+1)=3
We move all terms to the left:
(3y-2)/(2y+1)-(3)=0
Domain of the equation: (2y+1)!=0We multiply all the terms by the denominator
We move all terms containing y to the left, all other terms to the right
2y!=-1
y!=-1/2
y!=-1/2
y∈R
(3y-2)-3*(2y+1)=0
We multiply parentheses
(3y-2)-6y-3=0
We get rid of parentheses
3y-6y-2-3=0
We add all the numbers together, and all the variables
-3y-5=0
We move all terms containing y to the left, all other terms to the right
-3y=5
y=5/-3
y=-1+2/3
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