(3y-2)=(y+6)

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Solution for (3y-2)=(y+6) equation: 



(3y-2)=(y+6)

We move all terms to the left:

(3y-2)-((y+6))=0

We get rid of parentheses

3y-((y+6))-2=0



We calculate terms in parentheses: -((y+6)), so:

(y+6)

We get rid of parentheses

y+6

Back to the equation:

-(y+6)



We get rid of parentheses

3y-y-6-2=0

We add all the numbers together, and all the variables

2y-8=0

We move all terms containing y to the left, all other terms to the right

2y=8

y=8/2

y=4

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